XamBaaz
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India's personalised practice & revision platform for Class 8–12

Ace School Exams.Crack JEE & NEET.

XamBaaz is where you practise, learn and compete — quizzes at your level, revision notes, full mock tests, and an overall rank that moves with every quiz. Built for Class 8–12: CBSE Boards, IIT JEE, NEET & MHT-CET.

Bithindra Biswas, founder of XamBaazFounded by Bithindra BiswasIIM Ahmedabad · IIT Bombay faculty · 20+ yrs
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Class 10 · Physics · Light06:15
Question 4 / 10

An object is placed 30 cm from a convex lens of focal length 15 cm. The image distance is:

A convex lens with optical centre O, the foci F₁ and F₂ and the points 2F₁ and 2F₂ on the principal axis. An object stands 30 cm to the left of the lens. The focal length OF₂ is 15 cm.30 cmf = 15 cmOF₁2F₁F₂2F₂
A−30 cm
B30 cm
C10 cm
D15 cm
Class 11 · Physics · Kinematics✓ Correct +4

A particle moves with v = 4t² m/s. Its displacement after 3 seconds is:

B36 mYour answer ✓
Why

Displacement = ∫₀³ 4t² dt = [4t³/3]₀³ = 4·27/3 = 36 m. Integrate velocity over time — don't multiply v by t when v isn't constant.

+4 right−1 wrong0 skipped
Class 10 · Maths · Circles11:02
Question 7 / 10

PA and PB are tangents from an external point P to a circle with centre O. If ∠APB = 80°, then ∠POA is:

A circle with centre O. Tangents PA and PB from an external point P touch the circle at A and B, with right-angle marks at A and B, and OP is dashed. The angle APB is marked 80° and the angle POA is marked with a question mark.80°?OPAB
A50°
B100°
C40°
D80°
Your analytics · Physics72% avg

Accuracy by chapter

Laws of Motion88%
Kinematics72%
Gravitation54%
Thermodynamics38%
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Divakar SirTeacherPhysics Teacher · Mumbai
XamBaaz is a fantastic tool for any teacher looking to drive real concept clarity. It shows me which topics need re-teaching, while the NCERT-aligned adaptive practice keeps my students genuinely prepared for exam pressure. It's made monitoring student progress effortless and accurate. The platform's exam-grade marking and instant doubt-clearing with Genie help students to fix mistakes on their own.
AyushiStudentClass 9 Student · Mumbai
XamBaaz makes studying for school exams much easier. The concepts are explained in a simple way, and the quizzes help me practise and check how well I've understood each chapter. I especially like that I can learn a concept, practise it, and quickly see where I'm making mistakes. It makes exam preparation feel much less stressful and more organised.
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Class 9 · Science · Medium4 / 10

20 g of common salt is dissolved in 80 g of water. The mass percentage of solute is:

  • A25%✕
  • B15%
  • C20%✓
  • D80%
Why
Mass percent = 20 g salt ÷ (20 + 80) g total × 100 = 20%. The denominator is the full solution mass, solute plus solvent, not the solvent alone.
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Concept of the day
Class 9 · Science · Atomic Foundations of Matter
Law of conservation of mass

In a chemical reaction mass is neither created nor destroyed, so the total mass of products equals that of the reactants.

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  • Atomic Foundations of Matter85%
  • Tissues in Action72%
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Ranked by all the XP they have earned on XamBaaz, among XamBaaz students across India — the same order as their Current Rank in the app. Updated daily.

  1. 1AshClass 98,146XP in total
  2. 2Amulyaa P.Class 96,487XP in total
  3. 3Tanish G.Class 93,950XP in total
  4. 4Praveen M.Class 112,535XP in total
  5. 5Siyona A.Class 92,190XP in total

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One year from the day you pay. Your class stays the same till 31 March; on 1 April it moves up automatically and the rest of your year carries over.

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Start a timed chapter quiz now for CBSE Boards, JEE or NEET. Finish every chapter, then take the Subject Mastery Test.